A car and a large truck traveling at the same speed collide head-on and stick together. Which vehicle experiences the larger change in the magnitude of its momentum

Both vehicles experience the same change in momentum

Explanation:

Let m represent the mass of the vehicle, and 2m represent the mass of the large truck, and let v represent their initial speed, we have;

The total initial momentum, given as follows;

= 2·m·v - m·v = m·v

The total final momentum, = (2·m + m) ×

By the principle of conservation of linear momentum, the total initial momentum = The total final momentum

m·v = (2·m + m) ×

m·v = 3·m·

∴ v = 3 ×

= v/3

The change in the momentum for the large truck = 2·m·v - 2·m·

Therefore;

The change in the momentum for the large truck = 2·m·v - 2·m·v/3 = 2·m·(v - v/3)

The change in the momentum for the large truck = 2·m·(v - v/3) = 2·m·2·v/3 =  4·m·v/3

The change in the momentum for the car = m·v - m·(-) = m·v - m·(-v)/3 = m·v + m·(v)/3 = 4·m·v/3

Therefore, the change in the momentum for the large truck = The change in the momentum for the car and both vehicles experience the same change in momentum.

170m

Explanation:

V=d/t

V= velocity

D= displacement

T=time

D=v*t

D=17*1000

D= 17000cm

Convert to metres

D= 17000/100

D= 170m