Physics: A car braked with a constant deceleration of 36 ft/s2, producing skid marks measuring 50 ft before coming to a stop. How fast was the car traveling when the brakes were first applied

The answer is A. Series circuits can only follow one possible path....

A car braked with a constant deceleration of 36 ft/s2,

gracie0818

06.05.2021

Initial velocity u = 60 ft/s

Explanation:

Given:

Deceleration a = -36 ft/s²

Distance covered s =50ft

Final velocity v = 0 ft/s

Find:

Initial velocity u

Computation:

Using third equation of motion;

v² = u² + 2as

0² = u² + 2(-36)(50)

0 = u² - 3600

u² = 3600

u = 60 ft/s

Initial velocity u = 60 ft/s

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