A car hits another car from the back with an impulse of 5000 Ns. The car was in contact with the other car for 0.005 sec during the collision. What force does
the car applied on the other car?

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Ответ:

ogiebert

18.04.2023

Physics

$\boxed{q = 1.2 \times {10}^{ - 6} C}$

Explanation:

$f_e = \frac{{q}^{2}k }{ {r}^{2} } \\ q = \sqrt{ \frac{f_e( {r}^{2} )}{k} } = \sqrt{ \frac{5.2(5 \times {10}^{ - 2} )^{2} }{9 \times {10}^{9} } } \\ q =\sqrt{ \frac{5.2(5 \times {10}^{ - 2} )^{2} }{9 \times {10}^{9} } } = \sqrt{ \frac{0.013}{9 \times {10}^{9} } } \\ q = 1.2 \times {10}^{ - 6}$

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A car hits another car from the back with an impulse of 5000 Ns. The car was in contact with the other car for 0.005 sec during the collision. What force does the car applied on the other car?