A car is moving with a constant speed v around a level curve. The coefficient of friction between the tires and the road is 0.40. What is the minimum radius of curve if the car is to stay on the road?
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Ответ:
Minimum radius of the curve to stay on the road will be equal to
Explanation:
We have given coefficient of kinetic friction![\mu =0.40](/tpl/images/0586/6669/25142.png)
Acceleration due to gravity![g=9.8m/sec^2](/tpl/images/0586/6669/d7979.png)
We have to find minimum radius of the curve so that car will stay on the road
For the car to stay on the road centripetal force must be equal to frictional force
So![\frac{mv^2}{r}=\mu mg](/tpl/images/0586/6669/c6a2c.png)
So minimum radius of the
So minimum radius of the curve to stay on the road will be equal to![0.255v^2m](/tpl/images/0586/6669/5c37c.png)
Ответ:
abstract class Mark //Creating an Abstract class{
abstract double getPercentage();}
class A extends Mark{
double result;
A( int val1, int val2, int val3){
result=(val1+val2+val3)/3;}
double getPercentage(){
return result;}}
class B extends Mark{
double result;
B(int val1, int val2, int val3, int val4){
result=(val1+val2+val3+val4)/4;}
double getPercentage(){
return result;}}
class Main{
public static void main(String args[]){
//class A Object
Mark obj_1=new A(10,20,30);
System.out.println(obj_1.getPercentage());
//class B Object
Mark obj_2=new B(10,20,38,46);
System.out.println(obj_2.getPercentage());}}