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emarquez05
28.02.2020 •
Physics
A car is traveling at the posted speed limit of 6.70 m/s (15 miles/h) in a school zone. The car passing a school bus when a child darts out from in front of the bus. The car is 10.0 m from the child when the driver of the car applies the brakes. The car decelerates at a constant rate of 4.00 m/s2 until coming to a halt. Calculate the
(a) distance of the car travels while decelerating and
(b) distance required to stop if the car is initially traveling at 13.4 m/s (30.0 miles/h).
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Ответ:
5.6m and 22.4m
Explanation: from the 3rd equation of motion
v²=u²+2as
v²-u²=2as where : v=0 u=6.7m/s a=4m/s² s=?
0-6.7²=2×4×s
44.89=8s
s=44.89÷8
s=5.6m
for the second part, we shall still make use of the same equation.
v²-u²=2as where: a=4m/s² u=13.4m/s v=0 s=?
0-13.4²=2×4×s
179.56=8s
s=179.56/8
22.4m
Ответ: