A car travelled 60 km west in 1.33 h along straigt line , then returned back east for 40 km in 0.67 h . its average velocity
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Ответ:
7.29 km/h East
Explanation:
Velocity is distance covered per unit time, with consideration to the direction.
Taking East as positive then West is negative
Velocity when traveling towards West
V=d/t where d is distance and t is time taken. Substituting 60 km dor d and 1.33 for t then
V=-60/1.33=-45.112781954887 km/h West
Velocity when traveling towards East
V=d/t where d is distance and t is time taken. Substituting 40 km dor d and 0.67 for t then
V=40/0.67=59.701492537313 km/h East
Average velocity=(velocity East+West)/2
Average velocity is (59.701492537313+-45.112781954887)/2=7.29 km/h
Since the average is positive, then the direction is East
Therefore, the average velocity is 7.29 km/h East
Ответ:
I think the answer is patterns