A charge of −25µC is distributed uniformly over the surface of a spherical conductor of radius 12.0 cm. Determine the electric field (in N/C) due to this charge at the following distances from the center of the sphere. (Enter the radial component of the electric field.)a) 5cmb) 10cmc) 50cm
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Ответ:
a) 0 b) 0 c) -9*10⁵ N/C
Explanation:
a)
In electrostatic conditions, no electric field can exist inside a conductor.As the distance r=5 cm falls inside the conductor, the electric field is just zero.b)
Same as above, as r=10 cm is still inside the spherical conductor.c)
At r= 50 cm. from the center of the spherical conductor, we can apply Gauss' Law in order to get the value of the electric field.By symmetry, the electric field, at a same distance from the center, must be radial, and constant on a spherical surface concentric with the spherical conductor.So, we can write the following equation for Gauss'Law:Ответ:
I would provide an explanation but I know you're in a hurry. The answer is C. Lead or platinum only.