a concave mirror forms an errect image 30cm away from the object. If the image height is 2times the height of the object,find the object and image length. (ii) what is the focal length?

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Ответ:

shahfaisal

01.08.2022

Physics

0.04895m

Explanation:

Given magnetic field $B=1.5mT=1.5\times 10^{-3}T$ , Length of wire l=2.2m , current I=1.3A and $\mu_o=4\pi .10^-^7 N.A^-^2$ , the diameter, of the coil is calculated as:

$B=\frac{N\mu_o I}{d}, l=N2\pi r=N\pi d, N=l/\pi d\\\\\therefore d^2=\frac{l\mu_o I}{B} \\\\d=\sqrt{\frac{l\mu_o I}{B} }\\\\d=\sqrt{\frac{2.2\times 4\pi \times 10^{-7}\times 1.3}{0.0015}}\\\\d=0.04895m$

Hence, the diameter of the coil is 0.04895m

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a concave mirror forms an errect image 30cm away from the object. If the image height is 2times the height of the object,find the object and image length. (ii) what is the focal length?​