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07.03.2020 •
Physics
A constant force of magnitude 4.9 N makes an angle of 130o (measured counterclockwise) with the positive x direction as it acts on a 2.0 kg object moving in the xy plane. How much work is done on the object by the force as the object moves from the origin to the point having position vector?
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Ответ:
Explanation:
A constant force of 4.9 N is applied on the body in the horizontal and positive direction .
The object moves in x-y plane making an angle of 130° with horizontal .
Thus the work done can be calculated by the dot product of force and displacement S ( say )
Thus the work done = F . S = F S cos 130
= - 4.9 x 0.6 x S = - 3 S approx
Ответ:
B
Explanation: