A distant galaxy has a redshift z = 5.82 and a recessional velocity vr = 287,000 km/s (about 96% of the speed of light.) Notice that the equation z=vrcz=vrc does not hold true for recessional velocities approaching the speed of light. What is the distance to the galaxy in light years?

4100 Mpc

Explanation:

Since H o = 70 km/s/Mpc

Redshift z = 5.82

Recessional velocity vr = 287,000 km/s

Then, the distance to the galaxy in light years will be:

= Recessional velocity / H o

= 287000 / 70

= 4100 Mpc

Explanation:

In a group, 3 students measured the length of a pencil and obtained the following values: 16.2

cm, 16.5 cm and 16.1 cm, respectively. Find the average value of the measured values ​​and the errors obtained by each student.

Average value can be calculated by finding the mean of the values

Average value = Σx / N

A•V = (16.2 + 16.5 + 16.1) / 3

A.V = 48.8 / 3

A.V = 16.27cm

x~ = 16.27 cm

Each student error

If we assume the true value is average value, then, each student error can be calculated using

e = |x~ - x|

e = 16.27 - 16.2

e = 0.07 cm

Also,

e = 16.27 - 16.5

e = -0.23 cm

e = 0.23 cm, due to absolute value

Also,

e = 16.27 - 16.1

e = 0.17 cm

In Spanish

El valor promedio se puede calcular encontrando la media de los valores

Valor promedio = Σx / N

A • V = (16,2 + 16,5 + 16,1) / 3

A.V = 48.8 / 3

A.V = 16.27cm

x ~ = 16,27 cm

Cada error del alumno

Si asumimos que el valor verdadero es el valor promedio, entonces, cada error del estudiante puede calcularse usando

e = | x ~ - x |

e = 16,27 - 16,2

e = 0.07 cm

También,

e = 16.27 - 16.5

e = -0,23 cm

e = 0.23 cm, debido al valor absoluto

También,

e = 16.27 - 16.1

e = 0,17 cm