aliami0306oyaj0n
20.03.2020 •
Physics
A Frisbee of radius 0.15 m is accelerating at a constant rate from 7.1 revolutions per second to 9.3 revolutions per second in 6.0 s. What is its angular acceleration?
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Ответ:
17.03 rad/s^2
Explanation: One of the equation of motion that defines a circular motion with constant acceleration is given below as
ω = ω0 + αt
Where ω = final angular velocity = 9.3 rev/s
ω0 = initial angular velocity = 7.1 rev/s
α = angular acceleration = ?
t = time taken = 6.0s
By substituting the parameters, we have that
9.3 = 7.1 +α(6)
9.3 - 7.1 = 6α
16.3 = 6α
α = 16.3/6
α = 2.71 rev/s^2
We can also give the answer in rad/s^2 ( another unit of angular acceleration) by multipying by 2π
Hence, α = 2.71 × 2π , where π = 3.142
α = 17.03 rad/s^2
Ответ: