Physics: A galvanometer has full scale deflection current of 500 micro-Ampere, and resistance of 100 Ohm. Shunt with what resistance has to be combined with the galvanometer in order to transform it to an ammeter able to measure current of 10 Ampere full scale?

A galvanometer has full scale deflection current

Cocco

18.01.2022

resistance of shunt required = 5 ohms

Explanation:

A shunt is a low resistance that is connected in parallel to a galvanometer in order to convert it to a voltmeter.

since the shunt and galvanometer are connected in parallel, then voltage across the galvanometer is equal to voltage across the shunt.

$V_{s} = V_{g}\\ V=IR\\I_{s}R_{s}=I_{gR_{g} }$

$R_{s}=\frac{I_{g}R_{g} }{I_{s} }$

$R_{s}= \frac{500*10^{-3}*100 }{10}$

$R_{s}=$ 5Ω

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yousifgorgees101

22.01.2020

The answer is 13 however make sure if they ask for a certain measurement like meter answer it by saying 13 meters.

Explanation:

This basically turns into basic algebra if you know the formula for work. The formula for work is W=F*d

Here are the variables that you know 650J=50N*d so you need d.

All you do is divide 650J by 50N and you get a total of 13 (meters since I don't know what they want you to put it in).

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