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snurpeisov
28.06.2020 •
Physics
A gas fills the right portion of a horizontal cylinder whose radius is 5.33 cm. The initial pressure of the gas is 2.29 x 105 Pa. A frictionless movable piston separates the gas from the left portion of the cylinder that is evacuated and contains an ideal spring, as the drawing shows. The piston is initially held in place by a pin. The spring is initially unstrained, and the length of the gas-filled portion is 18.9 cm. When the pin is removed and the gas is allowed to expand, the length of the gas-filled chamber doubles. The initial and final temperatures are equal. Determine the spring constant of the spring.
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Ответ:
k = 5406.88 N/m
Explanation:
Since the initial and final temperatures are constant while the gas expands, the expansion of the gas obeys Boyle's law
Initial gas pressure,![P_1 = 2.29 * 10^5 Pa](/tpl/images/0696/4734/4d887.png)
Let the initial gas volume
= V
Volume = Length * Area
Since the cross sectional area does not change and the length of the gas-filled chamber is said to double, then the volume also doubles.
The final gas pressure,
will be gotten from the Boyle's law equation
The Cross Sectional Area,![A = \pi R^2](/tpl/images/0696/4734/715bf.png)
R = 5.33 cm = 0.0533 m
The force exerted on the piston, F = P₂ A
F = 1.145 * 10⁵ * 0.0089
F = 1021.9 N
To get the spring constant, use Hooke's law
F = k Δx
Where Δx = l₂ - l₁
Δx = 2l - l = l ( since the length of the chamber doubles on expansion)
Δx = 18.9 cm = 0.189 m
F = k Δx
1021.9 = k * 0.189
k = 1021.9/0.189
k = 5406.88 N/m
Ответ: