a golf ball has a mass 0.046 kkg rests on a tee it is struck by a golf club with an effectiv mass of 0.22 and speed of 44 assuming the collision is elastic, find the speed of the ball when it leaves the tee

210 m/s

Explanation:

We will use this equation for an elastic collision:

m₁v₁ + m₂v₂ = m₁v₁ + m₂v₂  The left side of the equation is before the collision; the right side is after the collision.

In this case, m₁ = mass of golf ball (0.046 kg) and m₂ = mass of the golf club (0.22 kg).

Left side of equation:

v₁ is 0 m/s since the ball is at rest on the tee.

v₂ is 44 m/s, given in the problem.

Right side of equation:

v₁ is what we are trying to find.

v₂ is 0 m/s since the ball will be at rest on the ground.

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Plug these values into the elastic collision equation:

(0.046 kg)(0 m/s) + (0.22 kg)(44 m/s) = (0.046 kg)(v₁) + (0.22 kg)(0 m/s)

Simplify this equation.

(0.22 kg)(44 m/s) = (0.046 kg)(v₁)  

Get rid of the units.

(0.22)(44) = 0.046v₁

Multiply the left side of the equation.

9.68 = 0.046v₁

Divide both sides by 0.046.

210.434782609 = v₁ 210 m/s = v₁

The speed of the ball when it leaves the tee is about 210 m/s.

Pienso que no puesto que el "Big Bang" es nada más una teoría, no es algo comprobado por los científicos. Así que parte de las interferencias de la tele provienen de otra parte. ‍♀️