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arimarieestrada
18.02.2020 •
Physics
A heat engine operates at 30% of its maximum possible efficiency and needs to do 995 J of work. Its cold reservoir is at 22 ºC and its hot reservoir is at 610 ºC. (a) How much energy does it need to extract from the hot reservoir? (b) How much energy does it deposit in the cold reservoir?
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Ответ:
(a) The energy extracted from the hot reservoir (Qh) is 3316.67J
(b) The energy deposited in the cold reservoir (Qc) is 2321.67J
Explanation:
Part (a) The energy extracted from the hot reservoir (Qh)
e = W/Qh
where;
e is the maximum efficiency of the system = 30% = 0.3
W is the the work done on the system = 995 J
Qh is the heat absorbed from the hot reservoir
Qh = W/e
Qh = 995/0.3
Qh = 3316.67J
Part (b) The energy deposited in the cold reservoir (Qc)
e = W/Qh
W = Qh - Qc
where;
Qc is the heat deposited in the cold reservoir
e = (Qh - Qc)/Qh
Qh - Qc = e*Qh
Qc = Qh - e*Qh
Qc = 3316.67J - 0.3*3316.67J
Qc = 3316.67J - 995J
Qc = 2321.67J
Ответ: