Physics: A horizontal rifle is fired at a bull s-eye. The muzzle speed of the bullet is 700 m/s. The barrel is pointed directly at the center of the bull s-eye, but the bullet strikes the target 0.09 m below the center. What is the horizontal distance between the end of the rifle and the bull s-eye?

A horizontal rifle is fired at a bull s-eye. The muzzle

Ответ:

kevon9008

21.01.2022

Hi there!

We can begin by solving for the time taken for the bullet to travel a VERTICAL distance of 0.09 m due to the effects of gravity.

We can use the kinematic equation for uniform acceleration:

$d_y = v_{0y}t + \frac{1}{2}at^2$

Since there is no initial vertical velocity:

$d_y = \frac{1}{2}at^2$

Rearrange to solve for time. (a = g = 9.8 m/s²)

$t = \sqrt{\frac{2d}{g}}$

$t = \sqrt{\frac{2(0.09)}{9.8}} = 0.136 s$

Now, we can use the distance, speed, and time equation in the horizontal direction:

d_x = v_xt

Plug in the values:

$d_x = 700(0.136) = \boxed{94.89 m}$

0,0(0 оценок)

Ответ:

potato3999

10.10.2021

Physics

add force for it to increase the speed of the object and do the opposite; put force under it so it slows as its falling. ( like indoor skydiving, they use big fans to keep you in the air.

Explanation:

0,0(0 оценок)

A horizontal rifle is fired at a bull's-eye. The muzzle speed of the bullet is 700 m/s. The barrel is pointed directly at the center of the bull's-eye, but the bullet strikes the target 0.09 m below the center. What is the horizontal distance between the end of the rifle and the bull's-eye?

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Physics

Ask an AI advisor a question