A hydraulic device has two pistons, one with a small cross-section area and another piston with a larger cross-section area. If a given force is applied to the small piston, the output force on the larger-area piston will be

The output force on the larger area piston ( F ) = × A

Explanation:

Let

Area of the smaller cross section piston =

Force of the smaller cross section piston =

Area of the larger cross section piston = A

Force of the larger cross section piston = F

So the Pressure on the smaller cross section piston = ----------- (1)

And the Pressure on the larger cross section piston = -------------(2)

When a given force is applied to the small piston the pressure on the smaller piston is equal to pressure on the larger piston. i.e. equation (1) is equal to equation (2)

⇒ =

⇒ =

⇒ F = × A ------------(3)

This is the output force on the larger area piston.

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Explanation:

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