myanniespencer39
22.12.2021 •
Physics
A light square wire frame each side of which is 10cm long hangs vertically in the water with one side just touching the water surface. Find the additional force necessary to pull the frame of the water (T=0.074 n/m)
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Ответ:
All the way up, it'll keep going slower and slower until it completely runs
out of speed. Then, at the highest point, it'll start falling, and continue
falling faster and faster until it hits the ground.
So ... for any height you choose (less than the peak height), the projectile
will be at that height twice: once on the way up, and again on the way down.
All we have to do is find the two times when the projectile is at 192 feet, and we'll know that it's higher than 192 feet between those two times.
Fortunately, we have a second-degree equation for the height, so we know that the equation will have two solutions for any height less than the peak.
The Golden Equation: H = -16 t² + 112 t
We want to know: What time
is 't' when 'H' is 192' ? 192 = -16 t² + 112 t
Subtract 192 from each side: -16 t² + 112 t - 192 = 0
(Just to make it feel better,
multiply each side by -1 ): 16 t² - 112 t + 192 = 0
Divide each side by 16 : t² - 7 t + 12 = 0
Stuff this equation through
the quadratic formula, and
we discover that t = 3
and
t = 4 .
This just has the sweet feel
of success all over it.
The projectile is 192 ft above the ground at 3 seconds, on the way up,
and again at 4 seconds, on the way down. Between 3 and 4 seconds,
it's higher than that.
Choice-a is 3 < t < 4 .