A light wave in space is described by the general function: u(r, t) = 1 (2π) 3/2 Z dk A(k) e i(k·r−ωt) . (1) (a) Find the particular solution knowing that at t = 0 the wave is given by

hello your question is incomplete attached below is the complete question

Answer : attached below

Explanation:

A) finding the particular solution at t = 0

attached below is the detailed solution of the particular solution knowing that t = 0

v = 3.57 m / s

Explanation:

Let's use Newton's second law in the upper part of the circle, with the minimum speed so that the water does not rest on the circle, that is, the normal is zero

          W = m a

acceleration is centripetal

          a = v² / r

let's substitute

         mg = m v² / r

         v =

let's calculate

        v = ra 1.3 9.8

        v = 3.57 m / s