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samflores236
15.08.2020 •
Physics
A liquid of density 1250 kg/m3 flows steadily through a pipe of varying diameter and height. At Location 1 along the pipe, the flow speed is 9.93 m/s and the pipe diameter d1 is 11.1 cm. At Location 2, the pipe diameter d2 is 16.7 cm. At Location 1, the pipe is Δy=8.89 m higher than it is at Location 2. Ignoring viscosity, calculate the difference ΔP between the fluid pressure at Location 2 and the fluid pressure at Location 1.
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Ответ:
The pressure difference is![\Delta P = 1.46 *10^{5}\ Pa](/tpl/images/0722/6911/9a450.png)
Explanation:
From the question we are told that
The density is![\rho = 1250 \ kg/m^3](/tpl/images/0722/6911/e9d52.png)
The speed at location 1 is![v_1 = 9.93 \ m/s](/tpl/images/0722/6911/a25e7.png)
The diameter at location 1 is![d_1 = 11.1\ cm = 0.111 \ m](/tpl/images/0722/6911/a8aef.png)
The diameter at location 2 is![d_1 = 16.7\ cm = 0.167 \ m](/tpl/images/0722/6911/558d2.png)
The height at location 1 is![h_1 = 8.89 \ m](/tpl/images/0722/6911/e5d9d.png)
The height at location 2 is![h_2 = 1 \ m](/tpl/images/0722/6911/03a8d.png)
Generally the cross- sectional area at location 1 is mathematically represented as
=>![A_1 = 3.142 * \frac{ 0.111^2}{4}](/tpl/images/0722/6911/b9418.png)
=>![A_1 = 0.0097 \ m^2](/tpl/images/0722/6911/e23bb.png)
Generally the cross- sectional area at location 2 is mathematically represented as
=>![A_2= 3.142 * \frac{ 0.167^2}{4}](/tpl/images/0722/6911/f8886.png)
=>![A_2 =0.0219 \ m^2](/tpl/images/0722/6911/682bd.png)
From continuity formula
=>![v_2 = \frac{A_1 * v_1}{A_2 }](/tpl/images/0722/6911/bf4cd.png)
=>![v_2 = \frac{0.0097 * 9.93}{0.0219 }](/tpl/images/0722/6911/48d93.png)
=>![v_2 = 4.398 \ m/s](/tpl/images/0722/6911/c840b.png)
Generally according to Bernoulli's theorem
=>![P_2 - P_1 = \frac{1}{2} \rho (v_1 ^2 - v_2^2 ) + \rho* g (h_1 - h_2)](/tpl/images/0722/6911/14637.png)
=>![\Delta P = \frac{1}{2}* 1250* (9.93 ^2 - 4.398^2 ) + 1250* 9.8 (8.89- 1)](/tpl/images/0722/6911/44f63.png)
=>![\Delta P = 1.46 *10^{5}\ Pa](/tpl/images/0722/6911/9a450.png)
Ответ:
A=48 CM2
Explanation:
A=9 X 10
A=90 CM2 9-2=7
A=6 X 7
A=42 CM2
A=90-42
A=48CM2