sihamabdalla591
18.02.2020 •
Physics
A mass of 2.8 kg is connected to a horizontal spring whose stiffness is 6.5 N/m. When the spring is relaxed, x = 0. The spring is stretched so that the initial value of x = +0.14 m. The mass is released from rest at time t = 0.
Remember that when the argument of a trigonometric function is in radians, on a calculator you have to switch the calculator to radians or convert the radians to degrees. Predict the position x when t = 1.44 s:
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Ответ:
Position of x at t = 1.44s is - 0.0817 m
Explanation:
For the harmonic motion of the spring, the displacement is given by
x = A cos wt
A is the amplitude of displacement = 0.14 m
t = time = 1.44 s
w = angular frequency and for a spring's motion, it is given by
w = √(k/m)
k = spring's stiffness = 6.5 N/m
m = 2.8 kg
w = √(6.5/2.8) = 1.524 rad/s
x = 0.14 cos (1.524 × 1.44) = 0.14 cos 2.194 = 0.14 × - 0.5836 = - 0.0817 m
Ответ:
Kinetic energy of the vehicle is
Explanation:
Kinetic Energy of the vehicle is given as
now we have
m = 1860 kg
now we have