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Trendymwah4211
08.08.2021 •
Physics
A model car moves round a circular path of radius 0.3m at 2 revolutions per secs what is its angular speed, the period of the car and the speed of the car
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Ответ:
a) T = 0.5 s
b) v = 1.2π m/s ≈ 3.77 m/s
Explanation:
It makes two revolutions in one second so makes one revolution in ½ second
circumference of the circle is
C = 2πr = 0.6π m
which it traverses in one time period
0.6π m / 0.5 s = 1.2π m/s
Ответ:
Explanation:
After 9 seconds displacement is zero
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = ?
Acceleration, a = -9.81 m/s²
Time, t = 9 s
Displacement, s = 0
Substituting
s = ut + 0.5 at²
0 = u x 9 + 0.5 x -9.81 x 9²
u = 44.15 m /s
Initial velocity is 44.15 m/s
Now we need to find speed when displacement is -23 m
We have equation of motion v² = u² + 2as
Initial velocity, u = 44.15 m/s
Acceleration, a = -9.81 m/s²
Final velocity, v = ?
Displacement, s = -23 m
Substituting
v² = u² + 2as
v² = 44.15² + 2 x -9.81 x -23
v = 49 m/s
Distance traveled before stopping is 54.45 m
Speed of the rock just before it reaches the water 23.0 m below the point where the rock left your hand is 49 m/s