A(n) 131 g ball is dropped from a height
of 61.1 cm above a spring of negligible mass.
The ball compresses the spring to a maximum
displacement of 4.82755 cm.
The acceleration of gravity is 9.8 m/s2.
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Calculate the spring force constant k.
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Ответ:
26.59 N/m
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 131 g
Extention (e) = 4.82755 cm
Acceleration due to gravity (g) = 9.8 m/s²
Spring constant (K) =?
Next, we shall convert 131 g to Kg. This can be obtained as follow:
1000 g = 1 Kg
Therefore,
131 g = 131 g × 1 Kg / 1000 g
131 g = 0.131 Kg
Thus, 131 g is equivalent to 0.131 Kg.
Next, we shall the force exerted by the ball on the spring. This can be obtained as follow:
Mass (m) = 0.131 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Force (F) =?
F = ma
F = 0.131 × 9.8
F = 1.2838 N
Next, we shall convert 4.82755 cm to metre (m)
This can be obtained as follow:
100 cm = 1 m
Therefore,
4.82755 cm = 4.82755 cm × 1 m / 100 cm
4.82755 cm = 0.0482755 m
Thus, 4.82755 cm is equivalent to 0.0482755 m
Finally, we shall determine the spring constant as follow:
Force (F) = 1.2838 N
Extention (e) = 0.0482755 m
Spring constant (K) =?
F = Ke
1.2838 = K × 0.0482755
Divide both side by 0.0482755
K = 1.2838 / 0.0482755
K = 26.59 N/m
Thus the spring constant is 26.59 N/m
Ответ:
400kg
Explanation:
Density=800kg/m^3
Volume=0.5L
Mass=density x volume
Mass=800 x 0.5
Mass=400kg