A nonrelativistic electron is accelerated from rest through a potential difference. After acceleration the electron has a de Broglie wavelength of 750 nm. What is the potential difference though which this electron was accelerated? (h = 6.626 × 10-34 J · s, e = - 1.60 × 10-19 C, mel = 9.11 × 10-31 kg)
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Ответ:
Potential difference though which the electron was accelerated is![2.67\times 10^{-6}\ uV\ .](/tpl/images/0536/9910/54bcb.png)
Explanation:
Given :
De Broglie wavelength ,![\lambda=750\ nm.](/tpl/images/0536/9910/eff7d.png)
Plank's constant ,![h=6.626\times 10^{-34}\ J.s \ .](/tpl/images/0536/9910/4babc.png)
Charge of electron ,![e=-1.6\times 10^{-19}\ C.](/tpl/images/0536/9910/eb5d9.png)
Mass of electron , m=9.11\times 10^{-31}\ kg.![m=9.11\times 10^{-31}\ kg.](/tpl/images/0536/9910/57451.png)
We know , according to de broglie equation :
Now , we know potential energy applied on electron will be equal to its kinetic energy .
Therefore ,
Putting all values in above equation we get ,
Hence , this is the required solution.
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Explanation: