A particle is projected from an origin O at a velocity of (4i + 13j)m/s. Find the position vector of the particle 2 seconds after projection and the distance the particle is then from O(take g= 10m/s²

164.87 J

Explanation:

From the question,

Work done (W) = mghcosθ Equation 1

Where m = mass of the box, h = height, g = acceleration due to gravity, θ = angle to the vertical

Given: m = 25 kg, h = 2.6 meters, θ = 75°.

Constant: g = 9.8 m/s²

Substitute these value into equation 1

W = 25×9.8×2.6×cos75°

W = 164.87 J.