Physics: A person is swimming in a river with a current that has speed vR with respect to the shore. The swimmer first swims downstream (i.e. in the direction of the current) at a constant speed, vS, with respect to the water. The swimmer travels a distance D in a time tOut. The swimmer then changes direction to swim upstream (i.e. against the direction of the current) at a constant speed, vS, with respect to the water and returns to her original starting point (located a distance D from her turn-around

A person is swimming in a river with a current

kitttimothy55

28.01.2022

The time taken is $t_{out} = \frac{D}{v__{R}} + v__{S}}}$

Explanation:

From the question we are told that

The speed of the current is $v__{R}}$

The speed of the swimmer in direction of current is $v__{S}}$

The distance traveled by the swimmer is

The time taken to travel this distance is $t_{out}$

The speed of the swimmer against direction of current is $v__{s}}$

The resultant speed for downstream current is

$V_{r} = v__{S}} +v__{R}}$

The time taken can be mathematically represented as

$t_{out} = \frac{D}{V_{r}}$

$t_{out} = \frac{D}{v__{R}} + v__{S}}}$

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