A piston-cylinder device contains 3 kg of saturated water vapor at 200 kPa. Now heat is transferred to the system at constant pressure until the temperature reaches 200oC. Calculate the work done by the steam during this process.
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Ответ:
work done = 117 kJ
Explanation:
given data
mass m = 3 kg
constant pressure P = 200 kPa
temperature T = 200°C
solution
we know that work done by steam is express as
work done = pressure × ΔVolume 1
and here ΔVolume = final volume - initial volume
we use here steam table and get at pressure 200 kPa
final specific volume = 1.08052 m³/kg
and
initial specific volume = 0.885735 m³/kg
so here
ΔV = 3 × (1.08052 - 0.885735)
ΔV = 0.584 m³
so put value in equation 1 we get
work done by steam = 200 × 0.584
work done = 117 kJ
Ответ:
this is true
Explanation:
if the engine stopped then it woudnt be able to go faster if you wanted to so the engine keeps track so it can do better and so you can know how much pressure for the brake.