jaylene125
13.06.2020 •
Physics
A projectile is launched at ground level with an initial speed of 53.0 m/s at an angle of 35.0° above the horizontal. It strikes a target above the ground 2.50 seconds later. What are the x and y distances from where the projectile was launched to where it lands?
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Ответ:
x = 108.5 m y = 45.37 m,
Explanation:
This is a projectile launching exercise, the horizontal distance it reaches is called the range and can be found by the expression
x = v₀ₓ t
the initial hairiness is
v₀ₓ = v₀ cos θ
x = v₀ cos θ t
let's calculate
x = 53 cos 35 2.50
x = 108.5 m
the height of the projectile can be calculated with
y =v₀ t - ½ g t²
y = vo sin tea t - ½ g t²
y = 53 sin 35 2.50 - ½ 9.8 2.5²
y = 45.37 m
Ответ:
29.1 percent 6–78 An inventor claims to have developed a heat engine that receives 700 kJ of heat from a source at 500 K and produces 300 kJ of net work while Solution Solution
Explanation: