A proton moves straight upward (away fromthe ground) through a uniform magnetic fieldthat points from east to west and has a mag-nitude of 5.9 T.If the proton moves with a speed 3.6×107m/s through this field, what is the magnitudeof the force acting on it? The charge on aproton is 1.60×10−19.Answer in units of N
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Ответ:
E= 20 N/C
Explanation: Charge q = 2.5 C , force F = 50 N. F = qE and
E= F/q= 50N / 2.5 C = 20 N/C