A rock falls for 1.43 seconds how far did it fall? The falls's velocity is an acceleration of -9.81 m/s2

Explanation:

Generally from kinematics equations we have that

Here u is the initial velocity of the rock and the value is  0 m/s given that there was no information that it was in motion before the fall

substituting 1.43 s for t and for g we have that

=>    

The negative sign show that the displacement is in the direction of the negative y-axis

The answer is -10.03 meters

The first is to write out the parameters given in the question

time= 1.43 seconds

distance(s)= ?

acceleration(g)= - 9.81

The formula is given as follows

s= ut +  1/2gt²

= (0)(1.43) + 1/2(-9.81)(1.43²)

= 0 + (-4.905)(2.0449)

= - 10.03

Hence the distance is -10.03 meters

Please see the link below for more information

link

hello, i am papaguy.

i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!