A single, non-constant force acts in the x direction

Ответ:

quetzaliescalona

22.01.2022

Work done is given as

$W = \frac{1}{2}m(2Q + 3RT^2)(3RT^2)$

Explanation:

As we know that the position of object is given as

x(t) = P + Qt + Rt^3

now we know that rate of change in position of object is known as velocity

so we have

$v = \frac{dx}{dt}$

v = Q + 3Rt^2

now we have

initial speed at t = 0

v_i = Q

at t = T final speed is given as

v_f = Q + 3RT^2

now work done is change in kinetic energy

$W = \frac{1}{2}m(v_f^2 - v_i^2)$

$W = \frac{1}{2}m[(Q + 3RT^2)^2 - Q^2]$

$W = \frac{1}{2}m(2Q + 3RT^2)(3RT^2)$

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