lamooothegoat
14.07.2020 •
Physics
A space station of diameter 80 m is turning about its axis at a constant rate. If the acceleration of the outer rim of the station is 2.5 m/s2, what is the period of revolution of the space station?
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Ответ:
List what you know:
d = 147 m
t = 9.8 s
Now solve for s by plugging 147m in for d and 9.8s in for t.
s = 147m/9.8s = 15m/s
Russell’s speed was 15m/s