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danidavis2002
15.02.2020 •
Physics
A spring is used to launch a ball vertically into air. the spring has a spring constant of 200N/m and is compressed by 5cm. A ball of mass 10g is placed just above the spring. calculate assuming the spring transfers all of its energy to the ball, the velocity of the ball just as it launches.
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Ответ:
Mercury's orbital period is approximately 88 days
Explanation:
Mercury's orbit parameters given in the question are;
Mercury's aphelion distance, Rₐ = 0.467 AU
Mercury's perihelion distance,
= 0.308 AU
Therefore, the average distance from Mercury to the Sun, 'a', is given as follows;
By plugging in the values of 'Rₐ' and '
', we get;
a = 0.3875 AU
According to Kepler's third law, we have;
P² = k·a³
Where;
P = The orbital period of the plane
a = The average distance from Mercury to the Sun
k = Constant
When k = 1, we have;
P² = a³
∴ P = √(a³)
From which we have;
P = √(0.3875 AU)³ ≈ 0.241216804711 years
P ≈ 0.2412168 years
1 year = 365 days
∴ 0.241216804711 years = 0.241216804711 years × 365 days/year ≈ 88.0441337 days
0.241216804711 years ≈ 88.0441337 days ≈ 88 days
Mercury's orbital period, P ≈ 88 days.