Physics: A spring oscillator is designed with a mass of 0.223 kg. It operates while immersed in a damping fluid, selected so that the oscillation amplitude decreases to 1.00 % of its initial value in 9.07 s. Determine the damping coefficient b of the system.

A spring oscillator is designed with a mass of 0.223

AM28

23.01.2022

The damping coefficient of the system is 0.226.

Explanation:

Given:

Mass m = 0.223 kg

Time t = 9.07 sec

From the formula of amplitude,

$A = A_{o} e^{-\alpha t }$

Where $\alpha = \frac{b}{2m}$

Here amplitude decrease to 1%

So we write,

$0.01 = e^{-\alpha 9.07 }$

$\ln 0.01 = - \alpha 9.07$

$-4.605 = - \alpha 9.07$

$\alpha = 0.507$

Here $\alpha = \frac{b}{2m}$

Where b = damping coefficient

$b = \alpha 2m$

$b = 2 \times 0.507 \times 0.223$

b = 0.226

Therefore, the damping coefficient of the system is 0.226.

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SithLeo

18.01.2022

Chemical

Explanation:

The answer is C because it is a chemical reaction when it evaporates for the seawater

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