A square current loop 5.20 cm on each side carries a 460 mA current. The loop is in a 0.900 T uniform magnetic field. The axis of the loop, perpendicular to the plane of the loop, is 30° away from the field direction.
What is the magnitude of the torque on the current loop?

The magnitude of the torque on the current loop is 0.0055 Nm

Explanation:

Given data,

We  have the formula,

T= u x B

Where u=  i x A

T= i×A×B ×sin(30)

T=0.46×0.52² ×0.900×0.5

T=0.0055 Nm

The magnitude of the torque on the current loop is 0.0055 Nm

Power=720[watt]

Explanation:

We need to remember the definition of mechanical work which is equal to the product of the force applied by the distance traveled.

In this problem, we have to find the power which is defined as the work divided into the time in which such work is performed. This way if we have the displacement and the time, this will be the speed with which this work is done.