A stone is dropped from a high tower and 9.21 seconds later it hits the ground. How high is the tower?

S = 415.64m

Explanation:

Given the following data;

Time, t = 9.21secs

Since it's a free fall, acceleration due to gravity = 9.8m/s²

Initial velocity, u = 0

To find the height of the tower, we would use the second equation of motion;

Where;

S represents the displacement or height measured in meters. u represents the initial velocity measured in meters per seconds. t represents the time measured in seconds. a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

Height, S = 415.64m

Therefore, the tower is 415.64m in height.

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Explanation: