a tire is rolling along a road, without slipping with a velocity v. a piece of tape is attached to the tire. When the tape is opposite the road (at the top of the tire), its velocity with respect to the road is
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Ответ:
The right solution will be the "2v".
Explanation:
For something like an object underneath pure rolling the speed at any point is calculated by:
⇒![v_{rolling}=v_{translational}+v_{rotational}](/tpl/images/0713/5749/e6a90.png)
Although the angular velocity was indeed closely linked to either the transnational velocity throughout particular instance of pure rolling as:
⇒![\omega=\frac{v_{translational}}{r}](/tpl/images/0713/5749/852d8.png)
Significant meaning is obtained, as speeds are in the same direction. Therefore the speed of rotation becomes supplied by:
⇒![v_{rotational}=\omega \times r](/tpl/images/0713/5749/086da.png)
On substituting the estimated values, we get
⇒![=\frac{v_{translational}}{r} \times r](/tpl/images/0713/5749/7e608.png)
⇒![=v_{translational}](/tpl/images/0713/5749/1411f.png)
So that the velocity will be:
⇒![v_{rolling}=v+v](/tpl/images/0713/5749/ba487.png)
⇒![=2v](/tpl/images/0713/5749/8c37e.png)
Ответ:
Explanation:
because a new substance is formed from the change. we cant change the solid precipitate
back to its gaseous form. the change is irreversible.
this is what i understood from the diagram.
all might not be correct.