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beelcypher
21.09.2020 •
Physics
A toy rocket is launched with an initial velocity of 10.0 m/s in the horizontal direction from the roof of a 30.0 m -tall building. The rocket's engine produces a horizontal acceleration of (1.60 m/s3)t, in the same direction as the initial velocity, but in the vertical direction the acceleration is g , downward. Air resistance can be neglected. What horizontal distance does the rocket travel before reaching the ground?
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Ответ:
The toy rocket will do an horizontal distance of 27.793 meters before reaching the ground.
Explanation:
This rocket experiments a two-dimension motion consisting in a combination of vertical free-fall and a horizontal uniformly acclerated motion. Flight time is governed by vertical movement and can be found by using this formula:
Where:
If we know that
,
,
and
, then resulting polynomial is solved:
The time taken by the toy rocket is:
Now, the horizontal distance can be found by integrating acceleration function twice. That is:
If we know that
and
, then the horizontal position formula is:
Where:
Now, the horizontal distance before reaching the ground is found: (
)
The toy rocket will do an horizontal distance of 27.793 meters before reaching the ground.
Ответ:
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