A train moving at a constant speed on a surface inclined upward at 10.0° with the horizontal travels a distance of 400 meters in 5 seconds. Calculate the vertical velocity component of the train during this time period. A. 41.10 meters/second B. 19.23 meters/second C. 13.89 meters/second D. 41.70 meters/second E. 78.78 meters/second

C. 13.89 meters/second

Explanation:

If the velocity of the train is v=s/t, where s is the distance and t is time, then v=400/5=80m/s. To get the vertical component of the velocity we need to multiply the velocity v with a sin(α): Vv=v*sin(α), where Vv is the vertical component of the velocity and α is the angle with the horizontal. So:

Vv=80*sin(10)=80*0.1736=13.888 m/s. 

So the vertical component of the velocity of the train is Vv=13.888 m/s.

The side length was multiplied by 5.

Step-by-step explanation:

Area of square =

We are given that the area of square is

So,

So, the side of original square is A.

Area of square =

Area of enlarged square =

So,

So, the side of enlarged square is 5A.

So, the side of the enlarged square is 5 times the side of the original square.

Thus Option B is true .

The side length was multiplied by 5.