Daveandemily17
21.06.2020 •
Physics
A train starts from rest and accelerates uniformly, until it has traveled 5.6 km and acquired a velocity of 42 m/s. The train then moves at a constant velocity of 42 m/s for 420 s. The train then slows down uniformly at 0.065 m/s^2, until it is brought to a halt. What is the acceleration during the first 5.6 km of travel?
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Ответ:
0.1575 m/s^2
Explanation:
Solution:-
- Acceleration ( a ) is expressed as the rate of change of velocity ( v ).
- We are given that the trains starts from rest i.e the initial velocity ( vo ) is equal to 0. Then the train travels from reference point ( so = 0 ) to ( sf = 5.6 km ) from the reference.
- During the travel the train accelerated uniformly to a speed of ( vf =42 m/s ).
- We will employ the use of 3rd kinematic equation of motion valid for constant acceleration ( a ) as follows:
- We will plug in the given parameters in the equation of motion given above:
the acceleration during the first 5.6 km of travel is 0.1575 m / s^2
Ответ:
C
Step-by-step explanation:
Given
f(x) =
To evaluate f(a + 2) substitute x = a + 2 into f(x), that is
f(a + 2) = = → C