jahayla4life
07.04.2020 •
Physics
A two-slit arrangement with 60.3 μm separation between the slits are illuminated with 537.0-nm wavelength light. If a viewing screen is located 2.14 m from the slits, find the distance on the screen from the first dark fringe on one side of the central maximum to the second dark fringe on the other side.
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Ответ:
38.12 mm
Explanation:
In the interference pattern created by the diffraction of light through a double slit, the position of the maxima (bright fringes) are given by
where
m is the order of the maximum
D is the distance of the screen from the slits
d is the separation between the slits
On the other hand, the position of the minima (dark fringes) is given by
where
(m+1) is the order of the minima
In this problem we have:
D = 2.14 m is the position of the screen
So, distance of the first dark fringe (m=0) from the central maximum is
On the other side, the distance of the second dark fringe (m=1) from the central maximum is
Therefore, the distance between the two dark fringes is:
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