A waitperson pushes the bottom of a glass tumbler full of water across a tabletop at constant speed. The tumbler and its contents have a mass of 0.70 kg,
and the coefficient of kinetic friction for the surfaces in contact is 0.41. What force
does the waitperson exert on the glass?

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Ответ:

dustinralph9768

26.08.2022

Physics

The correct answer is B.

Explanation: Electric potential energy is defined as the potential energy which is needed to move a charge against an electric field.

Mathematically,

$U_e=\frac{kq_1q_2}{r}$

U_e = Electric potential energy

k = Universal gravitational constant

q_1,q_2 = charges of each object

r = distance between two charges.

As, the charges are same in the question, but the distance between them is changing, so the ratio of two electric potential energies are:

r_1=3mm

r_2=6mm

Electric potential energy at r = 3mm

$U_1=\frac{kq_1q_2}{3}$ and

$U_2=\frac{kq_1q_2}{6}$

Ratio of the two:

$\frac{U_1}{U_2}=\left(\frac{\frac{kq_1q_2}{3}}{\frac{kq_1q_2}{6}}\right)$

$\frac{U_1}{U_2}=\frac{6}{3}$

$U_2=\frac{U_1}{2}$

So, the electric potential energy of the charge is divided by 2

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A waitperson pushes the bottom of a glass tumbler full of water across a tabletop at constant speed. The tumbler and its contents have a mass of 0.70 kg, and the coefficient of kinetic friction for the surfaces in contact is 0.41. What force does the waitperson exert on the glass?