alexxreyess03
07.03.2020 •
Physics
A weight watcher who normally weighs 400 N stands on top of a very tall ladder so she is one Earth radius above the Earth's surface. How much would she weigh there
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Ответ:
Explanation:
The weight of the body on the surface of earth can be found by the relation
W₁ = I
Here G is gravitational constant and M is the mass of earth .
m is the mass of the body
and R is the radius of earth or the distance of body from the center of the earth .
Now she moves to height equal to R . Thus the distance from center of earth becomes 2 R .
Thus Weight now is W₂ = II
Dividing II by I , we have
=
But W₁ = 400 N
Thus W₂ = = 100 N
Ответ:
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