Physics: A0.40 kg object is attached to a spring with force constant 157 n/m so that the object is allowed to move on a horizontal frictionless surface. the object is released from rest when the spring is compressed 0.17 m. (a) find the force on the object. (b) find its acceleration at that instant.

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A0.40 kg object is attached to a spring with force

irlrisottonero

10.01.2022

Part a)

F = 26.7 N

Part b)

a = 66.7 m/s^2

Explanation:

Part a)

Force on the object due to spring force is given as

F = kx

here we know that

k = 157 N/m

x = 0.17 m

so we have

$F = 157\times 0.17$

F = 26.7 N

Part b)

Acceleration of the object is given as

$a = \frac{F}{m}$

$a = \frac{26.7}{0.40}$

a = 66.7 m/s^2

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