bluetigerbird4745
07.09.2019 •
Physics
A5.86 kg block initially at rest is pulled to the right along a horizontal surface by a constant, horizontal force of 14.4 n. the coefficient of kinetic friction is 0.14. the acceleration of gravity is 9.8 m/s 2 . find the speed of the block after it has moved 4.98 m. answer in units of m/s.
Solved
Show answers
More tips
- G Goods and services How to Choose the Best Publishing House for Your Children s Book: Tips and Recommendations...
- S Science and Technology When do we change our clocks?...
- A Animals and plants How to Teach Your Parrot to Talk?...
- F Family and Home How to Remove Fading from Clothes: Tips and Tricks...
- F Food and Cooking How to Make Polendwitsa at Home?...
- F Family and Home Parents or Environment: Who Has the Most Influence on a Child s Upbringing?...
- P Philosophy Unbelievable stories of encounters with otherworldly forces...
- L Leisure and Entertainment How to Choose the Perfect Gift for Men on February 23rd?...
- H Health and Medicine How to Treat Whooping Cough in Children?...
- H Health and Medicine Simple Ways to Lower Cholesterol in the Blood: Tips and Tricks...
Answers on questions: Physics
- M Mathematics What is the awnser to that question...
- M Mathematics Pls help ASAP for Brianlest...
- M Mathematics PLEASE HELP ASAP *TIMED TEST* What is the slope of the line represented by the equation y = 4/5x - 3?A: -3B: -4/5C: 4/5 D: 3...
- M Mathematics According to the bar chart what is the highest average?...
Ответ:
3.3m/s
Explanation:
1. Find the acceleration a:
Given: normal force: N, the horizontal force: F, friction coefficient: μ, mass: m, acceleration of gravity: g. The sum of all forces in the horizontal plane is:
∑F = ma = F - μN = F - μmg
Solve for the acceleration a:
(i) a = F/m - μg
2. Use the equations of motion to calculate the velocity v for a uniform acceleration a, time t and initial velocity v₀:
(ii) v = at + v₀
position x, initial position x₀:
(iii) x = 0.5at² + v₀t + x₀
Eliminate time t by plugging in eq. (ii) into eq. (iii) with v₀ = 0 and x₀ = 0:
(iv) x = 0.5v²/a
Solve for v:
(v) v = √(2xa) = √(2*x*( F/m - μg)) = √(2*4.89 * (14.4/5.86 - 0.14*9.8))
Ответ: