A500-gram mass is attached to a spring and executes simple harmonic motion with a period of 0.25 second. if the total energy of the system is 4j, find the force constant of the spring?

315.5 N/m

Explanation:

m = 500 g = 0.5 kg

T = 0.25 second

Total energy, E = 4 J

Let K be the spring constant.

The formula for the time period is given by

K = 315.5 N/m

The answer to your question is c 11 because the number of neutrons plus protons equals the atomic mass.

Explanation:

To calculate the atomic mass of a single atom of an element, add up the mass of protons and neutrons. Example: Find the atomic mass of an isotope of carbon that has 7 neutrons. You can see from the periodic table that carbon has an atomic number of 6, which is its number of protons.