justijust500
05.08.2019 •
Physics
A500-turn circular loop 15.0 cm in diameter is initially aligned so that its axis is parallel to the earth's magnetic field. in 2.77 ms the coil is flipped so that its axis is perpendicular to the earth's field. if a voltage of 0.166 v is induced in the coil, what is the value of the earth's magnetic field?
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Ответ:
The magnetic field would be B = 5.2 x T
Explanation:
The voltage that is obtained when the magnetic flux of a coil is altered is the induced emf.
The induced emf E = rate of change of magnetic flux
When the loop axis is parallel to the Earth's magnetic field the initial flux
is;
φ1 = NBAcosθ
Final flux = 0
Therefore the change in flux is dφ = NBAcosθ - 0
dφ = NBAcosθ
Given
the induced emf E = 0.166 V
the time dt = 2.77 ms = 2.77 x s
N = number of turns = 500
d = diameter = 15 cm /100 = 0.15 m
A = area of cross section = π/4 = π x (0.15m/4 = 0.0176715
B = magnetic field
The induced emf E can be expressed thus
E = dφ/dt
= NBAcosθ/dt
cosθ = 1
E =NBA/dt
0.166 = 500 x Bx 0.0176715/ 2.77 x
0.166 x 2.77 x = 500 x B x 0.0176715
0.00045982 = 8.83572934 B
B = 0.00045982 / 8.83572934
B = 0.00005204097
B = 5.2 x T
Therefore the magnetic field would be B = 5.2 x T
Ответ:
kinetic energy
Explanation:
Kinetic energy is the form of energy related to the motion of an object. The kinetic energy of an object is given by:
where m is the mass of the object and v its speed. Therefore, any object in motion has kinetic energy: in this case, the bowling ball is in motion before the collision, so during the collision it transfers its kinetic energy to the pins.