A55 newton force applied on an object moves the object 10 meters in the same direction as the force. what is the value of work done on the object? a. 0 joules b. 5.5 joules c. -5.5 joules d. 5.5 × 102 joules e. -5.5 × 102 joules reset next

Option D: 5.5×10²Joules

Explanation:

Work done is the product of applied force and displacement of the object in the direction of force.

W = F.s = F s cosθ

It is given that the force applied is, F = 55 N

The displacement in the direction of force, s = 10 m

The angle between force and displacement, θ = 0°

Thus, work done on the object:

W = 55 N × 10 m × cos 0° = 550 J = 5.5 × 10² J

Hence, the correct option is D.