A6kg rock is thrown vertically upward from the top of a cliff that is 28m high. it was thrown with a speed of 11ms . calculate the greatest height of the rock as measured from the base of the cliff.

H=34.05m

Explanation: H=u²/2g+ 28m height of the cliff

u=11ms⁻¹

g=10ms⁻²

H=11²/2*10

H=121/20

H=6.05+28

H=34.05m

3.7 m/s^2

Explanation:

The period of a pendulum is given by:

where L is the length of the pendulum and g is the free-fall acceleration on the planet.

In this problem, we know that the period of the pendulum on Earth is:

while the period of the same pendulum on Mars is

And since the length of the pendulum L does not change, we can write:

where

is the free-fall acceleration on Earth

is the free-fall acceleration on Mars

Re-arranging the equation and substituting numbers, we find: