Physics: A75-m-long train begins uniform acceleration from rest. the front of the train has a speed of 18 m/swhen it passes a railway worker who is standing 125 m from where the front of the train started. what will be the speed of the last car as it passes the worker?

A75-m-long train begins uniform acceleration from - id752310604, alanisalvarez2000

lberman2005p77lfi

02.01.2022

22.76 m/s

Explanation:

Given

Train length(L)=75 m

Front of train after travelling 125 m is 18 m/s

Time taken by the front of train to cover 125 m

v^2-u^2=2as

$18^2-0=2\times a\times 125$

a=1.296 m/s^2

Speed of the last part of train when it passes the worker i.e. front of train has to travel has to travel a distance of 125+75=200 m

v^2-u^2=2as

$v^2=2\times 1.296\times 200$

$v=\sqrt{518.4}=22.76 m/s$

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